algorithm'''problem solve
[백준] 1389 - 케빈 베이컨의 6단계 법칙(설명X)
JunHwa Park
2020. 4. 30. 22:58
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 | #include <cstdio> int main() { int N, M; scanf("%d %d", &N, &M); int** arr = new int* [N + 1]; for (int i = 1; i <= N; i++) { arr[i] = new int[N + 1]; for (int j = 0; j <= N; j++) arr[i][j] = 1000000000; arr[i][i] = 0; } for (int i = 0; i < M; i++) { int edge1, edge2; scanf("%d %d", &edge1, &edge2); arr[edge1][edge2] = 1; arr[edge2][edge1] = 1; } for (int i = 1; i <= N; i++) for (int j = 1; j <= N; j++) for (int k = 1; k <= N; k++) arr[j][k] = arr[j][k] > arr[j][i] + arr[i][k] ? arr[j][i] + arr[i][k] : arr[j][k]; int person = 1, min = 1000000000; for (int i = 1; i <= N; i++) { int sum = 0; for (int j = 1; j <= N; j++) sum += arr[i][j]; if (min > sum) { person = i; min = sum; } } printf("%d\n", person); } | cs |